5 5 study guide and intervention solving polynomial equations

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NAME DATE PERIOD 55 Study Guide and Intervention Solving Polynomial Equations Factor Polynomials For any number of terms, check for: greatest common factor For two terms, check for: Difference of

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NAME
5-5
DATE
PERIOD
Study Guide and Intervention
Solving Polynomial Equations
Factor Polynomials
For any number of terms, check for:
greatest common factor
For two terms, check for:
Difference of two squares
a 2 - b 2 = (a + b)(a - b)
Sum of two cubes
a 3 + b 3 = (a + b)(a 2 - ab + b 2)
Difference of two cubes
a 3 - b 3 = (a - b)(a 2 + ab + b 2)
Techniques for Factoring
Polynomials
For three terms, check for:
Perfect square trinomials
a 2 + 2ab + b 2 = (a + b)2
a 2 - 2ab + b 2 = (a - b)2
General trinomials
acx 2 + (ad + bc)x + bd = (ax + b)(cx + d)
For four or more terms, check for:
Grouping
ax + bx + ay + by = x(a + b) + y(a + b)
= (a + b)(x + y)
Factor 24x2 - 42x - 45.
First factor out the GCF to get 24x2 - 42x - 45 = 3(8x2 - 14x - 15). To find the coefficients
of the x terms, you must find two numbers whose product is 8 · (-15) = -120 and whose
sum is -14. The two coefficients must be -20 and 6. Rewrite the expression using -20x and
6x and factor by grouping.
8x2 - 14x - 15 = 8x2 - 20x + 6x - 15
Group to find a GCF.
= 4x(2x - 5) + 3(2x - 5)
Factor the GCF of each binomial.
= (4x + 3)(2x - 5)
Distributive Property
2
Thus, 24x - 42x - 45 = 3(4x + 3)(2x - 5).
Exercises
Factor completely. If the polynomial is not factorable, write prime.
1. 14x2y2 + 42xy3
14xy 2(x + 3y)
4. x4 - 1
(x 2 + 1)(x + 1)(x - 1)
7. 100m8 - 9
(10m 4 - 3)(10m 4 + 3)
Chapter 5
2. 6mn + 18m - n - 3
(6m - 1)(n + 3)
5. 35x3y4 - 60x4y
5x 3y(7y 3 - 12x)
8. x2 + x + 1
prime
3. 2x2 + 18x + 16
2(x + 8)(x + 1)
6. 2r3 + 250
2(r + 5)(r 2 - 5r + 25)
9. c4 + c3 - c2 - c
c(c + 1)2(c - 1)
29
Glencoe Algebra 2
Lesson 5-5
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
Example
NAME
DATE
5-5
Study Guide and Intervention
PERIOD
(continued)
Solving Polynomial Equations
Solve Polynomial Equations
If a polynomial expression can be written in quadratic
form, then you can use what you know about solving quadratic equations to solve the
related polynomial equation.
Example 1
Solve x 4 - 40x 2 + 144 = 0.
x4 - 40x2 + 144 = 0
Original equation
2 2
2
(x ) - 40(x ) + 144 = 0
Write the expression on the left in quadratic form.
2
2
(x - 4)(x - 36) = 0
Factor.
2
x -4=0
or
x2 - 36 = 0
Zero Product Property
(x - 2)(x + 2) = 0
or
(x - 6)(x + 6) = 0
Factor.
x - 2 = 0 or x + 2 = 0
or x - 6 = 0 or x + 6 = 0
Zero Product Property
x = 2 or
x = -2
or
x = 6 or
x = -6 Simplify.
The solutions are ±2 and ±6.
Example 2
x - 15 = 0.
Solve 2x + √
2x + √x - 15 = 0
2(√x ) 2+ √x - 15 = 0
(2 √x -5)(√x + 3) = 0
2 √x - 5 = 0 or √x + 3 = 0
√x
= -3
Write the expression on the left in quadratic form.
Factor.
Zero Product Property
Simplify.
Since the principal square root of a number cannot be negative, √x = -3 has no solution.
25
1
The solution is −
or 6 −
.
4
4
Exercises
Solve each equation.
1. x4 = 49
, ±i √
± √7
7
4. 3t6 - 48t2 = 0
0, ±2, ±2i
7. x4 - 29x2 + 100 = 0
±5, ±2
10. x - 5 √x + 6 = 0
4, 9
Chapter 5
2. x4 - 6x2 = -8
3. x4 - 3x2 = 54
±2, ± √
2
±3, ±i √
6
5. m6 - 16m3 + 64 = 0
2, -1 ± i √
3
8. 4x4 - 73x2 + 144 = 0
3
±4, ± −
6. y4 - 5y2 + 4 = 0
±1, ±2
7
1
9. −
-−
2
x + 12= 0
x
1 1
−
,−
2
3 4
11. x - 10 √x + 21 = 0
9, 49
2
−
1
−
12. x 3 - 5x 3 + 6 = 0
27, 8
30
Glencoe Algebra 2
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
5
√x
or
=−
2
Original equation

NAME ______________________________________________ DATE______________________________ PERIOD ______________5-5 Study Guide and InterventionSolving Polynomial EquationsFactor PolynomialsTechniques for FactoringPolynomialsFor any number of terms, check for:greatest common factorFor two terms, check for:Difference of two squaresa2–b2= (a+b)(a–b)Sum of two cubesa3+b3= (a+b)(a2–ab+b2)Difference of two cubesa3–b3= (a–b)(a2+ab+b2)For three terms, check for:Perfect square trinomialsa2+ 2ab+b2=(a+b)2a2– 2ab+b2=(a−b)2General trinomialsacx2+ (ad+bc)x+bd= (ax+b)(cx+d)For four or more terms, check for:Groupingax+bx+ay+by=x(a+b) +y(a+b)= (a+b)(x+y)Example:Factor24x2– 42x– 45.First factor out the GCF to get24x2– 42x– 45 = 3(8x2– 14x– 15). To find the coefficients of thexterms, youmust find two numbers whose product is 8⋅(–15) = –120 and whose sum is –14. The two coefficients must be –20 and 6.Rewrite the expression using –20xand 6xand factor by grouping.8x2– 14x– 15 =8x2– 20x+ 6x– 15Group to find a GCF.

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paola dolcemascolo

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Elementary algebra, 100 m, 16 m, 4 M, 18m